C7H6O3 + CH3OH ——- C8H8O3 + H2O In an experiment 1.50 g of salicylic acid (C7H6O3) is reacted with 11.20 g of methanol (CH3OH). The yield of…

C7H6O3+CH3OH——-C8H8O3+H2OIn an experiment 1.50 g of salicylic acid (C7H6O3) is reacted with 11.20 g of methanol (CH3OH). The yield of methyl salicylate (C8H8O3) is 1.27g. What is the percentage yield? Which is the excess reactant ?

 

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